book-monads/src/ch04/s03-stackless.md
2023-05-03 12:05:38 +00:00

225 B

Stackless<'a> isn't covariant

Current hypothesis is that this comes from EvalTree<'a> being invariant over 'a due to FnOnce being invariant over its output, which in turn comes from present typesysten limitations.